QUESTION

Enter even number of elements and swap the adjacent elements of the ID array.

“TESTCASE_1”: “4\n10 20 30 40\n###—###SEPERATOR—###—\n20 10 40 30”, “TESTCASE_2”: “6\n11 12 13 14 15 16\n###—###SEPERATOR—###—\n12 11 14 13 16 15”, “TESTCASE_3”: “8\n2 8 9 4 8 6 5 8\n###—###SEPERATOR—###—\n8 2 4 9 6 8 8 5”, “TESTCASE_4”: “0\n###—###SEPERATOR—###—\n0”, “TESTCASE_5”: “0\n###—###SEPERATOR—###—\n0

ANSWER

#include <stdio.h>
int main()
{
  int n;
  scanf("%d",&n);
  int arr[n];
  int i;
  for(i=0;i<n;i++)
    scanf("%d",&arr[i]);
  for(i=0;i<n;i=i+2)
  {
    int t=arr[i];
    arr[i]=arr[i+1];
    arr[i+1]=t;
    printf("%d %d ",arr[i],arr[i+1]);
  }

	return 0;
}