QUESTION
Given a string S consisting of lowercase Latin letters, arrange all its letters in ascending order. \n\nInput:\n\nThe first line of the input contains T denoting number of testcases.Then follows description of each testcase.The first line of the testcase contains positive integer N denoting the length of string.The second line contains the string S.\n\n\nOutput:\n\nFor each testcase,output the sorted string.\n\n\nConstraints:\n\n1<=T<=100\n1<=N<=100.
“TESTCASE_1”: “1\n5\nedcab\n###—###SEPERATOR—###—\nabcde”, “TESTCASE_2”: “2\n6\nstring\n4\ndcba\n###—###SEPERATOR—###—\nginrst\nabcd”, “TESTCASE_3”: “0\n###—###SEPERATOR—###—\n0”, “TESTCASE_4”: “0\n###—###SEPERATOR—###—\n0”, “TESTCASE_5”: “0\n###—###SEPERATOR—###—\n0
ANSWER
#include <iostream>
using namespace std;
int main()
{int n,t;
char ch[100];
cin>>t;
for(int i=0;i<t;i++)
{cin>>n;
for(int j=0;j<n;j++)
cin>>ch[j];
char c;
for(int j=0;j<n-1;j++)
{for(int k=0;k<n-j-1;k++)
{if(ch[k]>ch[k+1])
{c=ch[k];
ch[k]=ch[k+1];
ch[k+1]=c;
}
}
}
for(int j=0;j<n;j++)
cout<<ch[j];
cout<<'\n';
}
return 0;
}