QUESTION
Write a program to find the majority element in the array. A majority element in an array A[] of size n is an element that appears more than n/2 times (and hence there is at most one such element). If input array doesn’t contain a majority element, then output \”NO Majority Element\”\n\nInput: The first line of the input contains T denoting the number of testcases. The first line of the test case will be the size of array and second line will be the elements of the array.\nOutput: For each test case the output will be the majority element of the array.\nConstraints:\n\n1 <=T<= 100\n\n1 <=N<= 100\n\n0 <= a[i]<= 100.
“TESTCASE_1”: “2\n5\n3 1 3 3 2\n3\n1 2 3\n###—###SEPERATOR—###—\n3\nNO Majority Element”, “TESTCASE_2”: “2\n7\n1 4 1 3 1 2 1\n5\n1 3 2 3 3\n###—###SEPERATOR—###—\n1\n3”, “TESTCASE_3”: “0\n###—###SEPERATOR—###—\n0”, “TESTCASE_4”: “0\n###—###SEPERATOR—###—\n0”, “TESTCASE_5”: “0\n###—###SEPERATOR—###—\n0
ANSWER
# include<stdio.h>
# define bool int
int findCandidate(int *, int);
bool isMajority(int *, int, int);
/* Function to print Majority Element */
void printMajority(int a[], int size)
{
/* Find the candidate for Majority*/
int cand = findCandidate(a, size);
/* Print the candidate if it is Majority*/
if (isMajority(a, size, cand))
printf("%d\n", cand);
else
printf("NO Majority Element\n");
}
/* Function to find the candidate for Majority */
int findCandidate(int a[], int size)
{
int maj_index = 0, count = 1;
int i;
for (i = 1; i < size; i++)
{
if (a[maj_index] == a[i])
count++;
else
count--;
if (count == 0)
{
maj_index = i;
count = 1;
}
}
return a[maj_index];
}
/* Function to check if the candidate occurs more than n/2 times */
bool isMajority(int a[], int size, int cand)
{
int i, count = 0;
for (i = 0; i < size; i++)
if (a[i] == cand)
count++;
if (count > size/2)
return 1;
else
return 0;
}
/* Driver function to test above functions */
int main()
{
int t;
scanf("%d", &t);
while(t--)
{
int size;
scanf("%d", &size);
int a[size], i;
for(i=0; i<size; i++)
scanf("%d", &a[i]);
printMajority(a, size);
getchar();
}
return 0;
}