HackerRank in a String!


We say that a string, s, contains the word hackerrank if a subsequence of the characters in s spell the word hackerrank. \n\nFor example, haacckkerrannkk does contain hackerrank, but haacckkerannk does not (the characters all appear in the same order, but it’s missing a second r).\n\nMore formally, let p0,p1,…,p9 be the respective indices of h, a, c, k, e, r, r, a, n, k in string s. If p0<p1<p2<..<p9 is true, then s contains hackerrank.\n\nYou must answer q queries, where each query i consists of a string, si. For each query, print YES on a new line if si contains hackerrank; otherwise, print NO instead.\n\nInput Format\n\nThe first line contains an integer denoting q(the number of queries). \nEach line i of the q subsequent lines contains a single string denoting si.\n\nConstraints\n2<=q<=10^2 \n\n10<=|si|<=10^4\n\nOutput Format\n\nFor each query, print YES on a new line if si contains hackerrank; otherwise, print NO instead.


import java.util.Scanner;

public class TestClass {
    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        int q = scan.nextInt();
        while (q-- > 0) {
            String str = scan.next();
            System.out.println(subsequenceExists(str) ? "YES" : "NO");
    private static boolean subsequenceExists(String str) {
        String hackerrank = "hackerrank";
        int index = 0;
        for (int i = 0; i < str.length(); i++) {
            if (str.charAt(i) == hackerrank.charAt(index)) {
            if (index == hackerrank.length()) {
                return true;
        return false;
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