Mia has discovered various rocks. Each rock is composed of various elements, and each element is represented by a lower-case Latin letter from ‘a’ to ‘z’. An element can be present multiple times in a rock. An element is called a gem if it occurs at least once in each of the rocks.\n\nGiven the list of N rocks with their compositions, display the number of gems that exist in those rocks.\n\nInput Format\n\nThe first line consists of an integer, N, the number of rocks. \nEach of the next N lines contains a rock’s composition. Each composition consists of lower-case letters of English alphabet.\n\nConstraints \n 1<=N<=100\nEach composition consists of only lower-case Latin letters (‘a’-‘z’). \n 1<=length of each composition<=100 \n\nOutput Format\n\nPrint the number of gems that are common in these rocks. If there are none, print 0.


using namespace std;
int main()
    int n,i,ans=0,ar[109][26]={},j,flag;
    cin >> n;
    string s;
    for(i=0; i<n; i++)
    cin >> s;
    for(j=0; j<s.size(); j++)
    for(i=0; i<26; i++)
    for(j=0; j<n; j++)
    cout << ans << endl;
    return 0;
Ads Blocker Image Powered by Code Help Pro

Ads Blocker Detected!!!

We have detected that you are using extensions to block ads. Please support us by disabling these ads blocker.

Powered By
Best Wordpress Adblock Detecting Plugin | CHP Adblock