QUESTION

Find the last occurrence of the index of the given integer\n\nThe index starts from \”0\”\n\nTestcase 1:\n\n1. Number of Inputs (6)\n\n2. The input elements (8 10 15 15 16 16) \n\n3. Element to be Searched (16)\n\nOutput :\n\n5\n\nExplanation :\n\nArray Index starts from \”0\” and 16 is found in array index 4 and 5 and the last index is 5\n\n\n\n.

“TESTCASE_1”: “6\n8 10 15 15 16 16\n16\n###—###SEPERATOR—###—\n5”, “TESTCASE_2”: “10\n10 20 55 11 22 22 11 33 55 10\n55\n###—###SEPERATOR—###—\n8”, “TESTCASE_3”: “5\n1 2 3 4 5\n2\n###—###SEPERATOR—###—\n1”, “TESTCASE_4”: “7\n1 2 3 4 5 6 7\n7\n###—###SEPERATOR—###—\n6”, “TESTCASE_5”: “0\n###—###SEPERATOR—###—\n0

ANSWER

#include <iostream>
#include<bits/stdc++.h>
using namespace std;
 
// Function for finding first and last occurrence
// of an elements
void findFirstAndLast(int arr[], int n, int x)
{
    int first = -1, last = -1;
    for (int i=0; i<n; i++)
    {
        if (x != arr[i])
            continue;
        if (first == -1)
            first = i;
        last = i;
    }
    if (first != -1)
        cout <<last;
    else
        cout << "Not Found";
}
 
// Driver code
int main()
{
  int n;
  cin>>n;
  int arr[n], i, x;
  for(i=0; i<n; i++)
    cin>>arr[i];
  cin>>x;
    
    findFirstAndLast(arr, n, x);
    return 0;
}